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Verizon [17]
2 years ago
10

Simon can climb up the balcony (5.11 m) in 4.2 seconds. What is Simon’s power?

Physics
1 answer:
dedylja [7]2 years ago
3 0

Answer:

77.3W (to 3sf)

Explanation:

weight = mass × gravtaional field strength

           = 6.35kg × 10N/kg

           = 63.5N

weight = force = 63.5N

work done = force × distance

                  = 63.5N × 5.11m

                  = 324.485J

power = \frac{work done}{elapsed time}

           = \frac{324.485J}{4.2s}

           = 77.3W (to 3sf)

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A uniform plank of length 5.0 m and weight 225 N rests horizontally on two supports, with 1.1 m of the plank hanging over the ri
lawyer [7]

Answer:

x = 0.6034 m

Explanation:

Given

L = 5 m

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d = 1.1 m

x = ?

We have to take sum of torques about the right support point.  If the board is just about to tip, the normal force from the left support will be going to zero.  So the only torques come from the weight of the plank and the weight of the man.

∑τ = 0  ⇒     τ₁ + τ₂ = 0  

Torque come from the weight of the plank = τ₁

Torque come from the weight of the man = τ₂

⇒  τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)

⇒  τ₂ = Wman*x = 522 N*x   (clockwise)

then

τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0

⇒  x = 0.6034 m

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