What is the distance an object would be from Earth if its parallax were one arcsecond?
1 answer:
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Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[]
x-x₀=6.05* m
=6.05 cm
Answer:
Explanation:
Given:
density,
diameter of the pipe,
pressure difference,
In case of pitot tube, the velocity is given by:
Now we know that volumetric flow rate is given as:
where :
a= cross sectional area of the pipe
v= velocity of flow