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vovangra [49]
2 years ago
8

Blood flows through the major artery at 1 m/s for 0.5 m then at a 0.6 m/s over a distance of another 0.5 m through the small art

ery. What is the average speed of blood
Physics
1 answer:
topjm [15]2 years ago
4 0

Blood flows through the major artery at 1 m/s for 0.5 m then at a 0.6 m/s over a distance of another 0.5 m through the small artery the average speed of blood is 0.4 m/s.

We know that average speed = \frac{0.5\times1+0.6\times0.5}{2}=0.4 m/s

Average speed is an important component in determining how long it takes to finish a journey. Average speed is simply a technique that assists us in calculating trip time and distance. It is obvious that the speed changes throughout the travel, making determining the average speed even more critical.

There are various methods for determining an object's or vehicle's average speed.

It is most desired when the speed of the object remains constant during the voyage, i.e. does not rise or decrease.

The approach for determining the average Speed is to divide. Divide the distance the vehicle travels by the time it travels to get the result.

Learn more about average speed brainly.com/question/12322912

#SPJ9

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A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050
Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

R=0.05Ω/Km*40km

R=2Ω

P=1000 MW

a).

P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k }  =8696.65A

Using law ohm

b).

V=I*R\\I=\frac{V}{R}

P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6}  W

e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12%

8 0
3 years ago
A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and
victus00 [196]

Answer:

a)  t=195.948N.m

b)  \phi=13.6 \textdegree

Explanation:

From the question we are told that:

Density \rho=1.225kg/m^2

Velocity of wind v=14m/s

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient \mu=2.05

a)

Generally the equation for Force is mathematically given by

F=\frac{1}{2}\muA\rhov^2

F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2

F=163.29

Therefore Torque

t=F*r*sin\theta

t=163.29*1.2*sin90

t=195.948N.m

b)

Generally the equation for torque due to weight is mathematically given by

t=d*Mg*sin90

Where

d=sin \phi

Therefore

t=sin \phi*Mg*sin90

195.948=833sin \phi

\phi=sin^{-1}\frac{195.948}{833}

\phi=13.6 \textdegree

5 0
3 years ago
10. Discrimination refers to behaviors that
salantis [7]

Answer:

d)

Explanation:

the only one that makes sense

4 0
3 years ago
When an unbalanced force acts on an object,
Gwar [14]
When balanced forces follow up on an object, the object won't move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.
6 0
3 years ago
Read 2 more answers
It takes a minimum distance of 76.50 m to stop a car moving at 15.0 m/s by applying the brakes (without locking the wheels). Ass
Vinvika [58]

The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.

<h3>Acceleration of the car </h3>

The acceleration of the car before stopping at the given distance is calculated as follows;

v² = u² + 2as

when the car stops, v = 0

0 = u² + 2as

0 = 15² + 2(76.5)a

0 = 225 + 153a

-a = 225/153

a = - 1.47 m/s²

<h3>Distance traveled when the speed is 32 m/s</h3>

If the same force is applied, then acceleration is constant.

v² = u² + 2as

0 = 32² + 2(-1.47)s

2.94s = 1024

s = 348.3 m

Learn more about distance here: brainly.com/question/4931057

#SPJ1

5 0
2 years ago
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