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lubasha [3.4K]
2 years ago
10

30 POINTS! The question is in the image! Answer choices: 8, 4, 7, 9

Mathematics
1 answer:
Ahat [919]2 years ago
3 0
\bold{ANSWER:}
EF = 7ft

\bold{EXPLANATIONS:}

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<h2></h2><h2>me.</h2>
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Step-by-step explanation:

8 0
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Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
We are going to sell Harlem Sweatshirts to raise money for
son4ous [18]

Answer:

32 sweatshirts

Step-by-step explanation:

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3 0
3 years ago
I need the word for this definition..... a number is the product of that number and any whole number
Oxana [17]
The answer to that definition is a multiple. A multiple is any number that is not zero.

Hope I helped!

- Amber
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3 years ago
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