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faust18 [17]
2 years ago
5

9 Below are the results of two polls of random samples of high school seniors

Mathematics
1 answer:
Ahat [919]2 years ago
5 0

Answer:

600

Step-by-step explanation:

10+12+100+120+30+300

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Runs 10 miles in 57 minutes. How many minutes does he take per miles?
evablogger [386]
5.1 i think. is it mutipul question
7 0
3 years ago
Read 2 more answers
I am thinking of two numbers.
taurus [48]

Answer:

6 and 8

Step-by-step explanation:

6+8=14 difference 2

5 0
2 years ago
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Let k ( x ) = 2 x + 3 and m ( x ) = 3 x 2 + 7 x − 10 . Find the indicated value. M ( k ( − 4 ) ) =
murzikaleks [220]

Answer: 30

Step-by-step explanation:

Given

k(x)=2x+3

M(x)=3x^2+7x-10

M\left(k(x)\right) is given by replacing the x by k(x) from the M(x)

\Rightarrow M\left(k(x)\right)=3(2x+3)^2+7(2x+3)-10\\\Rightarrow M\left(k(x)\right)=3(4x^2+9+12x)+14x+21-10\\\Rightarrow M\left(k(x)\right)=12x^2+50x+38

Now, M\left(k(-4)\right) is

\Rightarrow M\left(k(-4)\right)=12(-4)^2+50(-4)+38\\\Rightarrow M\left(k(-4)\right)=192-200+38\\\Rightarrow M\left(k(-4)\right)=30

8 0
3 years ago
What is -(3/7) x (-1/6)?
krok68 [10]
The answer is 1/14. -3/7 x -1/6. 3 crosses 6 2 time so you are left with -1/7 x -1/2 that is 1/14
3 0
3 years ago
Jim takes out a mortgage for 30 years at an interest rate of 2.49% and his monthly repayments are $986.50. What is the principal
Svetllana [295]

The principal loan amount will be 250000. P is denoted by the principal loan amount

<h3> What is the amount?</h3>

The complete repayment of money at the end of the period for which it was borrowed is referred to as the amount.

The given data in the problem is;

P is the principal loan amount

r is the rate of interest = 2.49%

n is the time period= of 30 years

The formula for the principal loan amount  is found as;

\rm P=M(1-(1+\frac{r}{12} )^{\frac{12}{n}

\rm P=986.50(1-(1+\frac{0.249}{12} )^{\frac{12}{30} }\\\\ P= 250000

Hence the principal loan amount will be 250000.

To learn more about the amount, refer to the link;

brainly.com/question/12184047

#SPJ1

6 0
1 year ago
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