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andriy [413]
2 years ago
11

The length of side AI is?

Mathematics
2 answers:
katen-ka-za [31]2 years ago
5 0
AI=3.25 and IH=4.2. This will be your answer
marissa [1.9K]2 years ago
3 0

Answer:

AI=3.25 IH= 4.2

Step-by-step explanation

The distance between C and D is 1.3 inches, the distance between E and F is 0.75 inches and the distance between G and H is 1.2 inches. This is true because the model says so. If you look closely together, this is equal to the distance between AI which is the length of AI. The answer would be 1.2+1.3+0.75=3.25. To find the length of side IH you do the same strategy, the distance between sides D and E is 4.8 inches, at the bottom is 9 inches of distance between side I and side F. 9-4.8 inches is equal to 4.2 inches. Therefore, the length of side AI is 3.25 inches and the length of side IH is 4.2 inches. If I am wrong please tell me for feedback, I also hoped that this has helped you in your learning :)

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Parabola Equations - Algebra
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Answer:

h=-\frac{1}{6}x^2+2x

Step-by-step explanation:

The height of the tunnel is modeled by:

h=rx^2+tx

Where r and t are constants.

We know that the maximum height of the tunnel h is 6 meters.

And at ground level, the width is 12 meters.

And we want to determine the equation of the parabola.

First, since this is a quadratic, our maximum height h will occur at the vertex of our equation.

The vertex is given by:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

In our case, we have the function:

h=(r)x^2+(t)x

Hence, a=r; b=t; and c=0.

Therefore, our vertex is:

\Rightarrow -\frac{t}{2r}

Thus, if we substitute this back into our equation, we should get 6 since 6 is the maximum height which is determine by the vertex. In other words:

(6)=r(-\frac{t}{2r})^2+t(-\frac{t}{2r})

Simplify:

6=r(\frac{t^2}{4r^2})-\frac{t^2}{2r}

Simplify:

6=\frac{t^2}{4r}-\frac{t^2}{2r}

Combine fractions:

6=\frac{t^2}{4r}-\frac{2t^2}{4r}=\frac{-t^2}{4r}

Multiply both sides by the denominator:

24r=-t^2

Let's solve for the constant r. Divide both sides by 24. Hence:

r=-\frac{t^2}{24}

Now, we can use our knowledge of the width.

We know that the width is 12 meters at ground level.

Hence, when h=0, the <em>difference of our roots</em> is 12.

So:

0=rx^2+tx

We can factor:

0=x(rx+t)

By the Zero Product Property:

x=0\text{ or } rx+t=0

So, the first zero is 0.

Therefore, the second zero <em>must be 12</em> to ensure that our width is 12.

Let's isolate the second zero. Subtract t from both sides:

rx=-t

Divide both sides by r:

x=-\frac{t}{r}

We know that this zero must be 12. Thus:

12=-\frac{t}{r}

We have previously solved for r. Substitute:

12=-\frac{t}{\frac{-t^2}{24}}

Simplify:

12=\frac{24}{t}

Take the reciprocal of both sides:

\frac{t}{24}=\frac{1}{12}

Multiply both sides by 24. Hence, the value of t is:

t=2

Now, we can find r. r is given by:

r=-\frac{t^2}{24}

By substituting 2 for t, then, we acquire that:

r=-\frac{(2)^2}{24}=-\frac{4}{24}=-\frac{1}{6}

Therefore, for:

h=rx^2+tx

Our equation is:

h=-\frac{1}{6}x^2+2x

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