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3 years ago

Which point could not be part of a function that includes (3,-1),(4,2),(5,4),(-2,0),and ( 8,-3)

1 answer:

3 0

(3,-1)

Use the V.L.T (Vertical Line Test) and plot the graph points, if you can draw a straight line through any points it cannot be a function.

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2 years ago

(-4, -7) and (-6, 9) in slope-intercept form. Show work

BigorU [14]

Answer:

Equation of line in slope-intercept form is: y = -8x-39

Step-by-step explanation:

Given points are:

(-4, -7) and (-6, 9)

The slope-intercept form is given by the equation

$y = mx+b$

Here m is the slope of the line and b is the y-intercept.

m is found using the formula

$m = \frac{y_2-y_1}{x_2-x_1}$

Here

(x1,y1) = (-4-7)

(x2,y2) = (-6,9)

Putting the values in the formula

$m = \frac{9+7}{-6+4} = \frac{16}{-2} = -8$

Putting slope in general equation

$y = -8x+b$

Putting (-6,9) in the equation

$9 = -8(-6)+b\\9 = 48+b\\b = 9-48\\b = -39$

Putting the value of b we get

$y = -8x-39$

Hence,

Equation of line in slope-intercept form is: y = -8x-39

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3 years ago