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2 years ago

Find the arc length of the partial circle.

Mathematics

1 answer:

Maurinko [17]2 years ago

5 0

Answer:

Arc length

$2\pi \times 8 \times \frac{90}{360} \\ 4\pi$

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Find the perimeter of a triangle with sides 12 inches, 9 inches, and 15 inches.

Artist 52 [7]

If its perimeter, it should be quite easy to find. Just add 12+9+15. Which equals 36. So the perimeter is 36 inches. -Hope it helps!

7 0

3 years ago

Read 2 more answers

katrin2010 [14]

AnsweI'm nauseous, I'm dyin'

(She ripped my heart right out)

Can't find her, someone to

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Lost it, riots

Gunfire inside my head, I've

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Step-by-step explanation:

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3 years ago

U divided by 3 = 6 what is U a solution to

drek231 [11]

Answer:

u=18

Step-by-step explanation:

u/3 =6

Multiply each side by 3

u/3*3 =6*3

u = 18

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3 years ago

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Last month, Ebony had 72 dollars in a checking account. The current balance is 126 dollars. What is the percent change in the ac

TEA [102]

Answer:

43%

Step-by-step explanation:

Last month, 72.

This month, 126.

Last month, ebony had 72/126 in her account to what she has this month. 72/126 as a percentage.

Ratio:

72:126

X100

7,200:12,600

÷126

57.142:100

Ebony had approximately 57% of her cash in her account last month, compared to this month.

5 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago