Select the graph that matches the equation y = −7 4 6 x + 12.

In this exercise, we are conducting many hypothesis tests to test a claim. Assume that the null hypothesis is true. If 400 tests

Brums [2.3K]

Answer:

Since the null hypothesis is true, finding the significance is a type I error.

The probability of the year I error = level of significance = 0.05.

so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5

Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.

3 0

2 years ago

to increase the mean of 4 numbers by 2, by how much would the sum of the 4 numbers have to increase? check image.

solong [7]

Answer:

8

Step-by-step explanation:

x=average

(x+x+x+x)/4=average

to increase x by 2 you add 2

x+2=average

(x+2+x+2+x+2+x+2)=4=(4x+8)/4=x+2

you'd have to increase the sum by 8 to make the numbers' averages' go up by 2

8 0

2 years ago

You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob

Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X 0 1 2

P(X) 42% 50% 8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c) P(win first game) = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X 0 1 2

P(X) 42% 50% 8%

P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value $\mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66$