9514 1404 393
Answer:
11
Step-by-step explanation:
The future value of the account is given by the formula ...
A = P(1 +r/12)^(12t) . . . . principal P invested at rate r for t years
Solving for t, we find ...
A/P = (1 +r/12)^(12t) . . . . . . . . . . . divide by P
log(A/P) = 12t·log(1 +r/12) . . . . . . take logs
Divide by the coefficient of t, then fill in the numbers.
t = log(A/P)/(12·log(1 +r/12)) = log(202800/93000)/(12·log(1 +.068/12))
t ≈ 11.497
It will take about 11 years for the account balance to reach the desired amount.
Use the pythagorean theorm
16^2 + 12^2 = c^2
256 + 144 = c^2
400 = c^2
c = 20 feet or a
Answer: the equation is
4x^2 + 4x - 12
Step-by-step explanation:
A quadratic equation is an equation in which the highest power of the unknown is 2.
The general form of a quadratic equation is expressed as
ax^2 + bx + c
Where
a is the leading coefficient
c is a constant
Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.
Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)
the equation becomes
(x+2)(x-1)
= x^2 - x +2x - 3
= x^2 + x - 3
Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes
4(x^2 + x - 3)
= 4x^2 + 4x - 12
Answer:
Out of the four, the only statement true about the parent and the transformed function is:
"The domain of the transformed function and the parent function are all real numbers."
Step-by-step explanation:
Parent function:
f(x) = |x|
Applying transformations:
1. Stretched by a factor of 0.3:
f(x) = 3|x|
2. Translated down 4 units:
f(x) = 3|x| - 4
Transformed function:
f(x) = 3|x| - 4
We can see that:
Range of the parent function = All real numbers greater than or equal to 0.
Range of the transformed function = All real numbers greater than or equal to -4.
Domain of the parent and the transformed function is same and equal to all real numbers.
Hence, the first three statements are wrong and the fourth one is true.
