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Elodia [21]
2 years ago
5

How do you figure this out? Keith plans to buy a car when he is 16. He currently has $3,000 saved up to buy the car. If his pare

nts plan to give him $2,500 as a birthday gift when he turns 16, and Keith wants to spend at least $2,000 of it on his $15,000 car. What is the most amount of money he would need to save each month now (for the next two years) now that he is anticipating his birthday gift?
Mathematics
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer:

He would need to save 500 dollars a month because 500x for two years (24 months) equals 12,000.

12,000 plus 3000 equals to 15,000

Step-by-step explanation:

hope this helps :)

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liq [111]

Answer:

[x-h]^2 + [y-k]^2 =r^2

Step-by-step explanation:

Let x and y be an arbitrary point along the circle

The equation of the circle is given as:

[x-h]^2 + [y-k]^2 =r^2

3 0
3 years ago
Which pair of complex factors results in a real number product? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)
photoshop1234 [79]

Answer:

(4 + 7i)(4 – 7i)

Step-by-step explanation:

This pair will produce a real answer because they are complex conjugates.

Complex conjugates ( a+bi) (a-bi)  when multiplied together form a real number ( a^2 + b^2)

6 0
3 years ago
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What is the end point and mid point
son4ous [18]
The endpoints are the points which represent or marks the end of a line segment or an interval. So, the endpoints would be the same points given which are ( 5/3, 1 ) and ( 0, 2). The midpoint, on the other hand, is the point that is located halfway through the line segment or the interval. It divides the segment into two parts with equal lengths. We calculate it by the formula,
midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

We substitute the points given above to the formula as follows:


midpoint = ((5/3 + 0) / 2, (1 + 2) / 2)
midpoint = 5/6 , 3/2

So, the midpoint is located at point 5/6, 3/2.
5 0
3 years ago
Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14-c^2-c-2/c^2-2c-15
matrenka [14]

<span>c^2 + 5c - 14 = 0 </span>
<span>(c-2)(c+7) = 0 </span>
<span>c-2 = 0 or c+7 = 0 </span>
<span>c = 2 or c = -7 </span>

<span>c^2 - 2c - 15 = 0 </span>
<span>(c-5)(c+3) = 0 </span>
<span>c-5 = 0 or c+3 = 0 </span>
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3 0
3 years ago
When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in i
Westkost [7]

Answer:

(1) 256 inches

(2) 5 feet

(3) 400 inches

(4) 10 feet

Step-by-step explanation:

(1) The function that gives the height in inches of the spray of water at a distance <em>x</em> from the sprinkler head is given as follows;

h(x) = 160·x - 16·x²

At x = 2 feet, we have;

h(2) = 160 × 2 - 16 × 2² = 256

Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches

(2) The x-coordinate, x_{max}, of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;

x_{max} = -b/(2·a)

The x-coordinate, x_{max}, of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;

x_{max} = -160/(2 × (-16)) = 5

Therefore, the number of feet along the way, the function will reach maximum height, x_{max} = 5 feet

(3) The function, h(x) = 160·x - 16·x², will reach maximum height, h_{max}, at x = 5, therefore;

h_{max} =  h(5) = 160 × 5 - 16 × 5² = 400

The maximum height of the spray, h_{max} = 400 inches

(4) The water is at ground level where h(x) = 0, therefore;

At ground level, h(x) = 0 = 160·x - 16·x²

160·x - 16·x² = 0

∴ 16·x × (10 - x) = 0

By zero product rule, we 16·x = 0, or (10 - x)  = 0, from which we have;

x = 0, or x = 10

The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.

7 0
3 years ago
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