Write the ratio 1 1/7:1/9 in simplest form

1 answer:

8 0

[tex]1\dfrac{1}{7}=\dfrac{1\cdot7+1}{7}=\dfrac{8}{7}\\\\1\dfrac{1}{7}:\dfrac{1}{9}=\dfrac{8}{7}:\dfrac{1}{9}=\dfrac{8}{7}\cdot\dfrac{9}{1}=\dfrac{72}{7}[tex]

Answer: 1 1/7 : 1/9 = 72 : 7

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$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got: