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1 year ago

7

Find the surface area of the solid shown or described. If necessary, round to the nearest tenth. Use the formula, write it out,

take your time. please help.

1 answer:

Mkey [24]1 year ago

7 0

$\bold{ANSWER:}$
163.9 m^2

$\bold{SOLUTION:}$

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What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2?<br><br> PLZ HELP!!!

olasank [31]

The first step in solving this is to substitute x with 3 and y with 2, so that
$\frac{1}{3} x^{2} +5.2y$
becomes
$\frac{1}{3} (3)^{2} +5.2(2)$
Then simply solve using the order of operations.
First exponents (there are no parentheses)
$\frac{1}{3} 9 +5.2(2)$
Then multiply and divide
$3+10.4$
And finally add and subtract
$13.4$
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>

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2 years ago

What are the answer to these? PLEASE ANSWER (don’t mind my work)

SSSSS [86.1K]

uno is the answer i believe

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3 years ago

Which of the following are valid (necessarily true) sentences? a. (∃x x = x) ⇒ (∀ y ∃z y = z). b. ∀ x P(x) ∨ ¬P(x). c. ∀ x Smart

Phantasy [73]

Answer:

b; ∀x P(x) ∨ ¬P(x)

Step-by-step explanation:

Suppose that we have a proposition p

Such that p can be true or false.

We can define the negation of p as:

¬p

Such that, if p is false, then ¬p is true

if p is true, then ¬p is false.

Also remember that a proposition like:

p ∨ q

is true when, at least one, p or q, is true.

Then if we write:

p ∨ ¬p

Always one of these will be true (and the other false)

Then the statement is true.

And if the statement depends on some variable, then we will have that:

p(x) ∨ ¬p(x)

is true for all the allowed values of x.

from this, we can conclude that the statement that is always true is:

b; ∀x P(x) ∨ ¬P(x)

Where here we have:

For all the values of x, P(x) ∨ ¬P(x)

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2 years ago

Hector is opening a bakery. He plans to start by selling cakes. It costs him $4 for each cake, $1.75 per box for the cakes, and

tatiyna

Answer:

D

Step-by-step explanation:

because if you add the numbers up you will get the answer easy :)

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2 years ago

Read 2 more answers

Please help with either of these questions. Put the answer in the comments please

Lena [83]

Answer:

2) distance = 4 km

Displacement = 4 km east

3) distance = 35 km

Displacement = 5 km north

Step-by-step explanation:

2. He runs for 3 km in the east direction and then stops.. He now runs another 1 km in the same direction then stops.. Thus,

Total distance covered = 3 + 1 = 4 km

Total displacement is how far he is from his starting point = 3 + 1 = 4 km east

3) Runs 20km north and then runs 15 km back from starting point.

Thus;

Total distance covered = 20 + 15 = 35 km

Total displacement is distance from starting point = 20 - 15 = 5 km north

Subtracted because an opposite direction was taken after the 20km back to her starting point.

6 0

2 years ago