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rusak2 [61]
2 years ago
5

Factorize this term: (a+b)raise to the power of 4 +4

Mathematics
1 answer:
zimovet [89]2 years ago
8 0

Answer:

<u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>

Step-by-step explanation:

Given :

  • (a + b)⁴⁺⁴

Solving :

  • (a + b)⁸
  • <u>(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)(a + b)</u>
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What is the reciprocal of 6/5? <br> A. 1 <br> B. 1 1/5 <br> C. 12/10 <br> D. 5/6
Sergio039 [100]
The reciprocal of 6/5 is D. 5/6

Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.

We need to get reciprocal of a fraction when division is performed.

For example: 2 ÷ 1/5

2 may be a whole number but in fraction form it is 2/1.

1st fraction = 2/1
2nd fraction = 1/5

In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.

1/5 ⇒ 5/1

Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10

So, 2 ÷ 1/5 = 10

8 0
3 years ago
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A road sign casts a shadow that is 4 feet long.At the same time a 6 foot man standing next to the sign casts a shadow that is 2.
lawyer [7]
The road sign would be 10ft tall.
3 0
3 years ago
A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The
Natasha_Volkova [10]

Answer:

The right answer is "0.2".

Step-by-step explanation:

The given values are:

\bar{x_0} = 3.7

s_o=4.95

t_{\frac{0.05}{2} }=2.2621

As we know,

95% confidence for \mu_0 will be:

= \bar{x_0} \pm t_{\frac{0.05}{2} },n-1\times \frac{s_o}{\sqrt{n} }

The lower bound will be:

= 3.7-2.2621\times \frac{4.95}{\sqrt{10} }

= 0.16\simeq 0.2

The upper bound will be:

= 3.7+2.2621\times \frac{4.95}{\sqrt{10} }

= 7.23\simeq7.2

Thus the right answer is "0.2"

8 0
3 years ago
Giải các phương trình vi phân sau<br> y' - y/x+1 = 2
KatRina [158]

It looks like the differential equation is

y'-\dfrac y{x+1}=2

Multiply both sides by 1/(<em>x</em> + 1) :

\dfrac{y'}{x+1}-\dfrac y{(x+1)^2} = \dfrac2{x+1}

The left side is now a derivative of a product,

\left(\dfrac y{x+1}\right)' = \dfrac2{x+1}

Integrate both sides with respect to <em>x</em> :

\dfrac y{x+1} = 2\ln|x+1|+C

Solve for <em>y</em> :

y = 2(x+1)\ln|x+1| + C(x+1)

3 0
3 years ago
Please answer right brineliest to wover right
MA_775_DIABLO [31]

Answer:

10

15

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-30

0

Step-by-step explanation:

8 0
3 years ago
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