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slega [8]
1 year ago
7

What is the nth term rule of the linear sequence below?

Mathematics
1 answer:
aleksklad [387]1 year ago
4 0

Answer:

a_n=5+2n

Step-by-step explanation:

Each term is 2 more than the previous term, so the common difference is 2.

Let a_n be the nth term of the sequence. Then, the first term is a_1=7.

The second term is a_2=7+2=9, and the third term is a_3=7+2+2=11.

Therefore, every term can be written as

a_n=7+\underbrace{2+2\cdots +2}_{n-1~\text{times}}.

Since repeated addition is multiplication, this can be written as

a_n=7+2(n-1),

which is the nth term rule of the linear sequence.

This could also be expanded to \boxed{a_n=5+2n.}

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Answer:

p+q = 10...... 1

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Step-by-step explanation:

The question is incomplete. Here is the complete question.

A student has 10 coins in her pocket that have a value of $0.85. The coins are either nickels or dimes. If each nickel costs $0.05 and each dime costs $0.10. Which system of linear equations represents this scenario?

Let the number of nickel in the pocket of the student be p

Let the number of dime in the pocket of the student be q

If there are 10 coins in her pocket, then the total coins in her pocket will be represented by the equation;

p+q = 10...... 1

If each nickel costs $0.05, p nickels will cost $0.05×p = $0.05p

If each dime costs $0.10, q nickel will costs $0.10×q = $0.10q

Total amount will be $0.05p+$0.10q

Now if the total coins in her pocket has a value of $0.85, then the we will equate $0.05p+$0.10q to $0.85 to give our second linear equation as:

$0.05p+$0.10q = $0.85 ....... 2

Therefore, the system of linear equations represents this scenario are:

p+q = 10...... 1

0.05p+0.10q = 0.85 ..... 2

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Answer:

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Step-by-step explanation:

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Hopefully this helps you :)

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