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Ksivusya [100]
2 years ago
9

Which early scientist theorized that the planets moved in elliptical orbits, or oval-like paths, around the sun?.

Physics
1 answer:
Black_prince [1.1K]2 years ago
6 0

Answer:

Johannes Kelper

Explanation:

<h2><em><u>THANKYOU</u></em><em><u>_</u></em><em><u>B</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>army</u></em></h2>

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What is the potential energy of a 2500 g object suspended 5 kg above the earth's surface?
Alinara [238K]

Answer:

potential \: energy = mgh \\  = ( \frac{2500}{1000} ) \times 10 \times 5 \\  = 125 \: newtons

if height is 5 m

8 0
3 years ago
Different forms of the same element are called what​
solmaris [256]

Answer:

Allotropes

Explanation:

Because it is the same element the chemical conposition is the same i.e. The atoms that make the substances are identical. Allotropes can be crystalline or amorphous and sometimes they can be varied in properties.

4 0
3 years ago
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Matter is anything that...
Lisa [10]
The answer is b, anything that has mass and takes up space

8 0
3 years ago
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Swimmers at the beach are tanning on towels. Which method of heat transfer is responsible for their tan? *
Free_Kalibri [48]

Answer:

ratiation

Explanation:

3 0
3 years ago
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Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro
luda_lava [24]

Answer:

c. 4.582\times10^{21} kg

Explanation:

r_{i} = Initial distance between asteroid and rock = 7514 km = 7514000 m

r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

M = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

8 0
4 years ago
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