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3 years ago

5

If a proton is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the proton w

ill be toward the ____ assuming the magnetic field is directed toward the north at this location.

1 answer:

pantera1 [17]3 years ago

3 0

Positive positive side naturally because protons always move to positive side and electron always move to negative side

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A typical carbon atom has six protons, six neutrons, and six electrons. Which of these has the least amount of mass?

Butoxors [25]

One proton or one neutron have very close to the same mass.

Their mass is about the same as the mass of 1,840 electrons !
So six electrons have roughly the same mass as 0.0033 of one
proton or one neutron.

Yes, these masses are very tiny. None of them was ever measured
until the 20th Century. But all of them have now been measured,
very precisely and accurately. This is very impressive, and should
give us a lot of admiration for scientists of the past hundred years.
It would be very interesting to look around online and find out
how they did it.

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2 years ago

A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the total distance walked by the hiker?

AnnyKZ [126]

Answer:

22 km

Explanation:

11km + 11km= 22km

3 0

3 years ago

Read 2 more answers

A professor sits on a rotating stool that is spinning at 10.0 rpm while she holds a heavy weight in each of her hands. Her outst

USPshnik [31]

Answer:

0.3950m

Explanation:

Use conservation of angular momentum:

Let L be the angular momentum(a vector).

We know that: $p=mv, L=l\omega, \ \ \ l=\sum (m_ir_i^2)}$ and that the two masses have the same radius:

$L_o=2mr_o^2\omega_o=L_f=2mr_f^2\omega_f\\\\r_o=0.795m,\omega_o=10\times2\pi \ rad/m , \omega_f=40.5\times 2\pi \ rad/m\\\\\therefore r_f=r_o\sqrt{(w_o/w_f)}\\\\r_f=0.795\sqrt{(10.0/40.5)}\\\\r_f=0.3950m$

Hence, the weights are 0.3950m away .

6 0

3 years ago

When you throw a pebble straight up with initial speed V, it reaches a maximum height H with no air resistance. At what speed sh

aev [14]

Answer:

Explanation:

Given

Initial speed is u=V

Maximum height of Pebble is H

Deriving maximum height of Pebble and considering motion in vertical direction

$v^2-u^2=2 as$

where v=final velocity

u=initial velocity

a=acceleration

s=Displacement

Final velocity will be zero at maximum height

$0-(V)^2=2\times (-g)\cdot H$

$H=\frac{V^2}{2g}$

i.e. maximum height is dependent on square of initial velocity

for twice the height

$2H=\frac{(V')^2}{2g}$

on comparing

$V'=\sqrt{2}V$

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3 years ago

A train is travelling at 15m/s. It accelerates at 3m/s² for 20 seconds. How far does the train travel in this time?

Fittoniya [83]

Answer:

Explanation:

The answer is 900m

4 0

3 years ago