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3 years ago

Problems with solar energy include ____.

Physics

2 answers:

lana66690 [7]3 years ago

8 0

The inability of current technology to store captured solar energy

MArishka [77]3 years ago

5 0

You have to save up some of what you get during the daytime, because you never get much at night.

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A baseball rolls off a 1.20m high desk and strikes the floor 0.50m away from the base of the desk . How fast was it rolling?

noname [10]

The initial velocity of the ball is 1.01 m/s

Explanation:

The motion of the ball rolling off the desk is a projectile motion, which consists of two independent motions:

- A uniform horizontal motion with constant horizontal velocity

- A vertical accelerated motion with constant acceleration ( $g=9.8 m/s^2$ , acceleration due to gravity)

We start by analyzing the vertical motion: we can find the time of flight of the ball by using the following suvat equation

$s=ut+\frac{1}{2}gt^2$

where

s = 1.20 m is the vertical displacement (the height of the desk)

u = 0 is the initial vertical velocity

$g=9.8 m/s^2$

t is the time of flight

Solving for t,

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(1.20)}{9.8}}=0.495 s$

Now we analyze the horizontal motion. We know that the ball covers a horizontal distance of

d = 0.50 m

in a time

t = 0.495 s

Therefore, since the horizontal velocity is constant, we can calculate it as

$v_x = \frac{d}{t}=\frac{0.50}{0.495}=1.01 m/s$

So, the ball rolls off the table at 1.01 m/s.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0

3 years ago

If you use a force of 90 N to pick up a 10 pound bag of charcoal, what is the acceleration?

hjlf

Answer:

9ms^2

Explanation:

since ,Force=mass*acceleration

then, acceleration=force/mass

and, Force=90N

Mass=10pound

therefore, acceleration=90/10

=9ms^2

8 0

3 years ago

A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom o

Jet001 [13]

Answer:

C) 3,000 kg m/s

Explanation:

We can consider the horizontal velocity of the motorcycle to be zero, since it rolls off the edge of the cliff very slowly. So, we only need to find the vertical velocity at the time of the impact with the ground.

The vertical velocity of the motorcycle at time t is given by (free-fall motion):

$v(t)=v_0 -gt$

where

$v_0=0$ is the initial vertical velocity (zero, since the motorcycle is not moving)

g = 9.8 m/s^2 is the acceleration due to gravity

t is the time

Since the motorcycle hits the ground after t = 3 seconds, we have

$v(3 s)=0-(9.8 m/s^2)(3 s)=-29.4 m/s$

And since we know its mass, m=100 kg, we can find its momentum:

$p=mv=(100 kg)(-29.4 m/s)=-2940 kg m/s \cdot -3000 kg m/s$

and the negative sign simply means downward direction.

8 0

3 years ago

.You have always been impressed by the speed of the elevators in your apartment building. You wonder about the maximum accelerat

AlexFokin [52]

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

3 0

3 years ago

Pls answer the 15a answer i cant understand it

Maksim231197 [3]

Materials required for the experiment of limiting force borne by string:-

String balance
weights
light strings
weight hanger
pan for spring balance
Sand

Steps of procedure for for the experiment of limiting force borne by string:-

First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
Add additional weight to the hanger again and again. And continue the same until the string is broken.
Note down the weight (x) where the string is broken.
Suspend spring balance to a support.
Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
Now place the weights (x-100 grams) in pan.
Observe the reading in the spring balance.
Add a small amount of sand in the pan by observing the readings.
same is to be done till the string is broken.

Learn more about limiting force here:- brainly.com/question/11371672

#SPJ1

6 0

1 year ago