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SVEN [57.7K]
2 years ago
10

Determine which expressions represent purely real numbers and which expressions represent non-real complex numbers. -i^2+i^3 7-5

i √ 6 0+9i √(-5)^2 -12 2 -7i^2
purely real number


non-real complex number

Mathematics
1 answer:
Roman55 [17]2 years ago
4 0

Purely real numbers are in the form of a+0i, while the Non-real complex numbers are in the form of a+bi.

<h3>What are Purely real numbers and Non-real complex numbers?</h3>

Purely real numbers are in the form of a+0i, while the Non-real complex numbers are in the form of a+bi.

The given expressions can be simplified in the following manner,

  • -i^2+i^3 = -(\sqrt{-1})^2+(\sqrt{-1} \times \sqrt{-1} \times \sqrt{-1}) = 1 -i
  • 7-5i
  • \sqrt{-6} = \sqrt{-1 \times 6} = \sqrt{-1} \times \sqrt{6} = 0+ i\sqrt{6}
  • i⁶ = (i²)³ = (-1)³ = -1 = -1 +0i
  • 0+9i
  • (\sqrt{-5})^2 = (\sqrt{-1 \times 5})^2 = -1 \times 5 = -5+0i
  • -12 = -12+0i
  • 2 -7i^2 = 2-7(-1) = 2+7 = 9+0i

Purely real numbers (a+0i)

  • -1 +0i
  • -5+0i
  • -12+0i
  • 9+0i

Non-real complex number (0+bi)

  • 1-i
  • 7-5i
  • 0+i√6
  • 0+9i

Learn more about Purely real numbers and Non-real complex numbers:

brainly.com/question/20410752

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9. 3x + 9y = 18<br> y = x + 2<br> Substitution method
777dan777 [17]

Answer:

x = 0

y = 2

Step-by-step explanation:

3x + 9y = 18 ---------eqn 1

y = x + 2---------eqn 2

Substitute eqn 2 into eqn 1, for the value of y

3x + 9( x + 2) = 18

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12x = 18 -18

12x = 0

Divide both sides by 12 , to get the value of x.

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Hint: to confirm the values

x = 0

y = 2

Let's take eqn 1 ,

3x + 9y = 18

3(0) + 9(2)

= 0 + 18

= 18

Correct

Let's take eqn 2

y = x + 2

Let's find y

y = 0 + 2

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Correct too

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