Answer:
C and D
Step-by-step explanation:
Answer:
Step-by-step explanation:
![(a)\\ \\ (i)\ \sqrt{3}=3^p\\ \\ 3^{\frac{1}{2}}=3^p\\ \\ p=\frac{1}{2}\\ \\ (ii)\ \frac{1}{9}=3^q\\ \\ 3^{-2}=3^q\\ \\ q=-2\\ \\ (b)\\ \\ 3^{\frac{1}{2}(3^x)=\frac{1}{9}\\ \\ 3^{\frac{1}{2}+x}=3^{-2}\\ \\ \frac{1}{2}+x=-2\\ \\ x=-1.5](https://tex.z-dn.net/?f=%28a%29%5C%5C%20%5C%5C%20%28i%29%5C%20%5Csqrt%7B3%7D%3D3%5Ep%5C%5C%20%5C%5C%203%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D3%5Ep%5C%5C%20%5C%5C%20p%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%20%5C%5C%20%28ii%29%5C%20%5Cfrac%7B1%7D%7B9%7D%3D3%5Eq%5C%5C%20%5C%5C%203%5E%7B-2%7D%3D3%5Eq%5C%5C%20%5C%5C%20q%3D-2%5C%5C%20%5C%5C%20%28b%29%5C%5C%20%5C%5C%203%5E%7B%5Cfrac%7B1%7D%7B2%7D%283%5Ex%29%3D%5Cfrac%7B1%7D%7B9%7D%5C%5C%20%5C%5C%203%5E%7B%5Cfrac%7B1%7D%7B2%7D%2Bx%7D%3D3%5E%7B-2%7D%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7D%2Bx%3D-2%5C%5C%20%5C%5C%20x%3D-1.5)
As can be noticed, 67,400 is the result of a number rounded to the nearest hundred.
the range of numbers which when rounded to the nearest hundred results in 67,400 is 67,350 to 67,449.
Therefore, the greatest whole number that rounds to 67,400 is 67,449 while the least whole number that rounds to 67,400 is 67,350.
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Yes because 2 divided by 5 is .4 , and .4 is a decimals and decimals are in rational numbers .