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Alina [70]
3 years ago
6

Which expression is equivalent to 9a + 12?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer: 3a+6a+6+6

Step-by-step explanation:

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HELP I NEED THIS DONE FAST
Rudiy27

Answer:

<h3>80.1 x 10 <em>7</em></h3>

Step-by-step explanation:

5 0
3 years ago
Complete the missing value/help?
blagie [28]

What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y

To solve this you just need to plug in -4 for y and solve for x

6x + 7(-4) = 4x + 4(-4)

6x - 28 = 4x - 16

Now isolate x by adding 28 to both sides

6x - 28 + 28 = 4x - 16 + 28

6x = 4x + 8

and subtract 4x from both sides

6x - 4x = 4x - 4x + 8

2x = 8

divide both sides by 2

2/2x = 8/2

x = 4

x = 4, y = -2

Answer: (4, - 2)

Hope it helps :)

Bransliest would be appreciated

5 0
3 years ago
Read 2 more answers
1.
Bad White [126]

first polygon

ext. angle=180°-120°

=60°

ext \: ang =  \frac{360}{n}

n=360°/60°

n=6

second polygon

n=2(6)=12

ext. ang= 360°/n = 360°/12° = 30°

int. ang = 180°-30°= 150°

answer is C

6 0
3 years ago
In the solution, 3b + 9c = 3(b + 3). What should be done to make it CORRECT?
stiks02 [169]

Answer:

The second term of the binomial factor should be 3c instead of 3.

Step-by-step explanation:

Distributive property:

a*b + a*c = a*(b +c)

3b + 9c = 3*b + 3* 3 *c = 3*(b + 3c)

7 0
3 years ago
Please help me I’m super confused on this problem!
Lorico [155]

Answer:

m < amc = 54°

Step-by-step explanation:

< amb and < bmc are complementary angles whose sum equals 90°.

Therefore, to find the value of 2x°, we must first solve for x.

We can establish the following equality statement:

< amb + < bmc = < amc

< 2x° + (x + 9)° = 90°

Combine like terms:

2x° + x° + 9° = 90°

3x° + 9° = 90°

Subtract 9 from both sides:

3x° + 9° - 9° = 90° - 9°

3x = 81°

Divide both sides by 3 to solve for x:

3x/3 = 81°/3

x = 27°.

Since x = 27°, substitute its value into 2x° to find m < amc:

2x° = 2(27°) = 54°

Therefore, m < amc = 54°

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
3 years ago
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