<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
should be 6
Step-by-step explanation:
Pythagorean Theorum was used.
Answer:363
Step-by-step explanation:
We have to find partial sum for the sequence 243 , 81 , 27 ..... up to 5 terms(S5 given)
The sequence actually is 3^5,3^4.,3^3.....
Therefore first 5 terms are 1) 3^5 I.e. 243
2) 3^4 I.e. 81
3) 3^3 I.e. 27
4)) 3^2 I.e. 9
5) 3^1 I.e. 3
Adding all those no. we get partial sum of first 5 no. of the sequence
So, 243 + 81 + 27 + 9 + 3
= 363
Hope it helps!!!
Answer:
28 yards
Step-by-step explanation:
It's perimeter so you add (6x2)+(8x2)
The x2 is because there's 2 of each side
