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guapka [62]
2 years ago
8

Two circles are concentric if they have the same center.

Mathematics
1 answer:
vaieri [72.5K]2 years ago
8 0

The equation of the circle is (x - 4)² + (y - 6)² = 16. The correct option is the second option (x - 4)² + (y - 6)² = 16

<h3>Equation of a circle </h3>

From the question, we are to determine the equation of the circle

The equation of circle is given by

(x - h)² + (y - k)² = r²

Where (h, k) is the center

and r is the radius

From the given information,

The two circles are concentric

∴ (h , k) = (4, 6)

But the other circle has a radius that is twice as large

∴ r = 2 × 2

r = 4

Thus,

The equation of the circle becomes

(x - 4)² + (y - 6)² = 4²

(x - 4)² + (y - 6)² = 16

Hence, the equation which represents a circle that is concentric with the circle shown but has a radius that is twice as large is (x - 4)² + (y - 6)² = 16. The correct option is the second option (x - 4)² + (y - 6)² = 16

Learn more on Equation of a circle here: brainly.com/question/1506955

#SPJ1

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Percent of change from $. 79 to 3.72
Anvisha [2.4K]

Answer:

470.89%

3.72 divided by 0.79 = 4.70886076

470.89%

Step-by-step explanation:

8 0
3 years ago
-4×+2=-5×+9 what do I do next?
AURORKA [14]
Subtract the 2 on both sides to get -4x=-5x+7, then add -5 on both sides and get 1x=7 then divide 1 on both side to get x=7
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3 years ago
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Total area of a cylinder
rusak2 [61]
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3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
Can someone explain how to find the answer to x​
OLga [1]

Answer:

130

Step-by-step explanation:

X is the alternate corresponding angle to 50.   50+y=180

y=130

x and y = the  same thing so 130 is the value of x

4 0
3 years ago
Read 2 more answers
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