If one kit contains 235 parts, then all we need to do to find out how many are in 4 of those same kits is multiply the amount in one kit by the amount of kits there are.
235 * 4 = 940
There are 940 parts in 4 of the kits.
Hope that helped! =)
Subtract 3 both sides first. R-3=ts²
next, divide both sides by t, (R-3)/t=s²
finally, take the square root of both sides
√(R-3)/t = s. 2nd choice.
Answer:
![20.5\%](https://tex.z-dn.net/?f=20.5%5C%25)
Step-by-step explanation:
Let's write out a case for two specific questions being correct and the rest being incorrect:
,
The
represents the chances of getting the question correct, as there are 5 answers and 1 correct answer choice.
The
represents the chances of getting the question incorrect, as there are 5 answers and 4 incorrect answer choices.
The equation above does show the student getting two answers correct and three answers incorrect, but it only shows one possible case of doing so.
We can choose any two of the five questions to be the ones the student gets correct. Therefore, we need to multiply this equation by the number ways we can choose 2 from 5 (order doesn't matter):
.
Therefore, the probability the student gets two questions correct is:
![\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \binom{5}{2}=\frac{1}{5}\cdot \frac{1}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot \frac{4}{5}\cdot 10=0.2048\approx \boxed{20.5\%}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%20%5Cbinom%7B5%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%20%5Cfrac%7B4%7D%7B5%7D%5Ccdot%2010%3D0.2048%5Capprox%20%5Cboxed%7B20.5%5C%25%7D)
Answer:
x^2
Step-by-step explanation:
all the numbers are square roots so n square is the nth term.
2^2= 4
3^2=9
4^2=16
5^2=25
6^2=36