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3 years ago

The area of a circle, in terms of

Mathematics

1 answer:

ch4aika [34]3 years ago

3 0

Answer:

30m

Step-by-step explanation:

A=πr²

225π=πr²

225=r²

r=√225

r=15

d=2r

d=2×15

=30m

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3 years ago

How do you solve 18x+27=117

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Step-by-step explanation:

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2 years ago

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3 years ago

Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein

Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = $\frac32$ meters

$\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}$

$\Rightarrow \frac{radius }{height}=\frac {3}{26}$

$\Rightarrow radius=\frac {3}{26}\times height$ ......(1)

The volume of the cone is $V=\frac13 \pi r^2 h$

Now putting $r=\frac{3}{26} h$

$V=\frac13 \pi (\frac3{26}h)^2 h$

$\Rightarrow V=\frac{3}{676} \pi h^3$

Differentiating with respect to t

$\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}$

$\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}$

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e $\frac{dh}{dt}=17$ cm/min

Putting $\frac{dh}{dt}=17$

$\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17$

$\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17$

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The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

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3 years ago

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guapka [62]

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