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dolphi86 [110]
2 years ago
14

Please help!!!!!!

Mathematics
2 answers:
vodka [1.7K]2 years ago
4 0

Answer:

A

Step-by-step explanation:

square: 10² = 100

Circle: π*5² = 3.14*25 = 78.5

In the squqre not in the circle: 100-78.5 = 21.5

mart [117]2 years ago
3 0
I also agree with answer a and the person above
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What is the Expected value of the probability distribution also called?
Fittoniya [83]

Answer:

The expected value is also known as the expectation, mathematical expectation, mean, average, or first moment.

8 0
3 years ago
Can you please help me? Thanks!!!!
ss7ja [257]
The answer is 25 degrees.

This is how you solve the equation, first you must know that the straight like ABC=180, DBC is 130, so the remaining amount is 50 degrees, BE is a bisector of ABD which means it splits ABD right down the middle. So ABE+EBD=50 degrees, 25+25=50 since both sides MUST be equal in order for BE to be a bisector of ABD.

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4 0
3 years ago
The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds,What perc
soldier1979 [14.2K]

Answer:

57.62% of players weigh between 180 and 220 pounds

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 25

What percent of players weigh between 180 and 220 pounds

We have to find the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 180.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{25}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881

X = 180

Z = \frac{X - \mu}{\sigma}

Z = \frac{180 - 200}{25}

Z = -0.8

Z = -0.8 has a pvalue of 0.2119

0.7881 - 0.2119 = 0.5762

57.62% of players weigh between 180 and 220 pounds

4 0
3 years ago
On a test with 25 problems, grace got 88% correct.How many promblems did Grace get wrong?
nignag [31]
25X4=100
4X_=88
88÷4=22
So she got 22 problems correct.
~JZ
Hope you understand
7 0
3 years ago
Sven investigates the amount of damage to the head gaskets on the trucks in his fleet and find that the damage index depends on
Tju [1.3M]

Answer:

the amount of damage to the head

4 0
4 years ago
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