The bearings from b to a is that o95 and it can’t be no longer than what I put so it has to be 20
First, since it's given the angle PRS=98 degrees we can find x.
(3x-8)+(2x+6)=98 we can solve for x
after solving this we find that
x=20
Now we can solve for angle QRS
2x+6 plug in our values and we get
40+6, which equals 46 degrees
3a= 3(5) = 15
15 - - 3 = 15+3 = 18
18/6 = 3
b + a = 5 + -3 = -3 + 5 = 2
3 x 2 = 6
You cannot assume that the angles are equal. there is no angle measure and nothing to say the lines are parellel.
The solution for a system of equations will be when the graphs touch each other, or intersect, and that happens when both equations equate each other, so, let's do so,
