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1 year ago

A man has a mass of 120kg, he reduces his mass by 15%, how many kilograms is that

Mathematics

2 answers:

Yuliya22 [10]1 year ago

6 0

Answer:

102 kg

Y = 120(1 - 0.15)

Y = 120(0.85)

Y = 102

Varvara68 [4.7K]1 year ago

5 0

Answer:

your answer should be 102kg i could be wrong.

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3 years ago

Which is greater than or less than

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3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

Solve 3y - 15 = y+1 with steps shown

bija089 [108]

Answer:

y = 8

Step-by-step explanation:

Hello!

We can solve for y by isolating it.

<h3>Solve for y</h3>

3y - 15 = y + 1
3y - 15 - y = y +1 - y
2y - 15 = 1
2y - 15 + 15 = 1 + 15
2y = 16
y = 16/2
y = 8

The value of y is 8.

4 0

1 year ago

Read 2 more answers

A man has a mass of 120kg, he reduces his mass by 15%, how many kilograms is that​

A man has a mass of 120kg, he reduces his mass by 15%, how many kilograms is that