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tankabanditka [31]
2 years ago
15

What’s the missing number for this equation:)

Mathematics
2 answers:
Softa [21]2 years ago
7 0

{\red\star}\:{\underline{\underline{\mathfrak{\purple{hello}}}}}\:{\red\star}

140x = 8400

\frac{140x}{140}  =  \frac{8400}{140}

x = 60

Our answer is 60.

Good luck.

Annette [7]2 years ago
3 0

Answer:

140 x X =8400

X=8400/140

X= 60

140 x 60 =8400

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CaHeK987 [17]

Answer:

1= 4x^2

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3= 3u^2v^2w

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3 years ago
The figure below shows a graph of the function of f(x) in the coordinate plane
Lana71 [14]

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Step-by-step explanation:

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2 years ago
Elaina wrote two correct variable expressions to represent the phrase “one-fourth of a number.” Which variable expressions could
ivolga24 [154]
The answer is n over 4 
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2 years ago
(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -
AveGali [126]

Answer:

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

5 (x - y + z) + (4x + 3y) =9x - 2y +5z

Step-by-step explanation:

Solving (i):

3 (a + 5b) + a (a + 4)

Open brackets

3 (a + 5b) + a (a + 4)  = 3a + 15b + a^2 + 4a

Collect like terms

3 (a + 5b) + a (a + 4)  = a^2 + 4a+3a + 15b

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

Solving (ii)

y (10 - y) + 3 (y - 2)

Open bracket

y (10 - y) + 3 (y - 2)  = 10y - y^2 + 3y - 6

Collect like terms

y (10 - y) + 3 (y - 2)  = - y^2+10y  + 3y - 6

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

Solving (iii)

2 (8a - 5b) + 3 (5a - 12)

Open bracket

2 (8a - 5b) + 3 (5a - 12)  = 16a -10b + 15a - 36

Collect like terms

2 (8a - 5b) + 3 (5a - 12)  = 16a+ 15a -10b  - 36

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

Solving (iv)

3 (y - 3) + ( 8 - 6y + x)

Open bracket

3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x

Collect like terms

3 (y - 3) + ( 8 - 6y + x) = 3y  - 6y + x- 9 + 8

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

Solving (v):

a (a - 2b) + b (b + 2a - c)

Open bracket

a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc

Collect like terms

a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2  - bc

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

Solving (vi)

5 (x - y + z) + (4x + 3y)

Open brackets

5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y

Collect like terms

5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z

5 (x - y + z) + (4x + 3y) =9x - 2y +5z  

6 0
3 years ago
Lines y and z are parallel.
Mrac [35]

Answer:

28 degrees

Step-by-step explanation:

step 1

Find the measure of angle 1

m\angle 1+65^o=180^o ----> by supplementary angles

m\angle 1=180^o-65^o=115^o

step 2

Find the value of x

(10x+5)^o=m\angle 1 ----> by corresponding angles

substitute

(10x+5)^o=115^o

10x=110\\x=11

step 3

Find the measure of angle 2

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

m\angle 1+m\angle 2+(4x-7)^o=180^o

substitute

115^o+m\angle 2+(4(11)-7)^o=180^o

m\angle 2=180^o-152^o=28^o

3 0
3 years ago
Read 2 more answers
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