Answer:
<h2>A
pproximately 4824 games </h2>
Step-by-step explanation:
Given that the sales made are 4,567 ,5430, 3998, 5,220,and 4,906
the average is (4567+5430+3998+5220+4906)/5
=24121/5
=4824.2
in the month of august let the sales be x
average= (4567+5430+3998+5220+4906+x)/6
the average for march to july is 4824.2
4824.2= (4567+5430+3998+5220+4906+x)/6
24121+x=4824.2*6
24121+x=28945.2
x=28945.2-24121
x=4824.2
approximately 4824 games
Answer:
D: 8
Step-by-step explanation:
7 + (2 + 6) ^2 ÷ 4 ⋅ (1/2)^4
According to PEMDAS
We to parentheses first
7 + (8)^ 2 ÷ 4 ⋅ (1/2)^4
Then we do exponents
7 + 64 ÷ 4 ⋅ (1/16)
The multiply and divide from left to right
7+64 ÷ 4 ⋅ (1/16)
7+16 ⋅ (1/16)
Then add and subtract from left to right
7+1
8
Answer:
8
Step-by-step explanation:
To find the median, look at the line in the box. it lines up with 8 on the number line. Therefore, 8 is the median.
Answer:
24
Step-by-step explanation:
a. The water in the second tank decreases at a faster rate than the water in the first tank. The initial water level in the first tank is greater than the initial water level in the second tank.
Step-by-step explanation:
Step 1:
It is given that the time remaining in first tank is given by the equation y = -10x + 80. We can get the total water in the tank by substituting x = 0 in the equation. The total volume of water in first tank is 80 litres.
Step 2:
The value of y in the equation y = -10x + 80 will be 0 when the tank is fully empty. When y = 0 , 10x = 80, so x = 8. We can conclude that the first tank empties fully in 8 minutes.
In 8 minutes 80 litres of water is emptied from first tank. So the water in the first tank decreases at rate of 80 / 8 = 10 litres per minute
Step 3:
As per the given table for the second tank, 60 litres of water remains when x =0. So the total volume of water in the second tank = 60 litres.
Step 4:
As per the given table for the second tank, the volume becomes 0 in 5 minutes. In 5 minutes 60 litres of water is emptied from second tank. So the water in second tank decreases at rate of 60 / 5 = 12 litres per minute.
Step 5:
The initial volume of water in first tank is higher. The water in second tank decreases at a faster rate than the first tank.
Step 6:
The only correct option is:
a. The water in second tank decreases at a faster rate than the water in the first tank. The initial water level in first tank is greater than the initial water level in the second tank.
