Answer:
they are not getting enough sunlight to begin with the growth tends to become weak
Explanation:
Answer:
its the midline, or the middle of the pig
Explanation:
Answer:
1. polarity
2. hydrogen bonding
3. High heat capacity
4. Adhesion
5. polarity
6. surface tension
7. high heat vaporization
8. hydrogen bonds form a rigid and stable network
9. Water is a polar substance and fat is a nonpolar substance.
10. Cohesion
Explanation:
Water is a polar molecule that is held together by hydrogen bonds to form strong cohesive forces. This accounts for the surface tension in water. Surface tension is the force acting on water that it makes to behave like a stretched elastic skin.
The polarity of water accounts for the fact that it is found in several parts of the body where it largely plays the role of a polar solvent.
High heat capacity of water enables it to function well in the area of thermoregulation in the body. High heat vaporization accounts for the fact that water helps maintain extreme temperature changes in an area.
When in solid state, the hydrogen bonded network in water becomes rigid and forms a very stable network of water molecules. Being polar, water does not interact with fat because like dissolves like.
In plants, the attachment of water to plant roots is known as adhesion and is necessary for the capillary movement of nutrients to plants via the root.
<h3><u>Benefits of smooth stem over rough stem:</u></h3>
Smooth stem plants like guava, eucalyptus etc do have a smooth layer of bark over its stem that comes out as a skin when they shed their barks. Whereas most of the other plants like mango, banyan etc do have a rough corrugated layer of bark over their stem.
The smooth stem doesn’t let water to accumulate in the bark which can led to infections to the tree. It also doesn’t allow any seed to settle on bark that can led to growth of parasites. Thereby this smooth bark saves the trees from some of the probable harm to the tree.
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.