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Tju [1.3M]
3 years ago
9

I have $25 all in nickels and dimes. There are twice as many Nickles as dimes. How many of each are there?

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

N=250

Step-by-step explanation:

 "twice as many nickels as dimes"     means    N =2D     [eq1]

 "collection of nickels and dimes is worth $25"    means

        5N + 10D = 2500      [eq2]

   (To avoid using decimal points, PLZ express everything in cents.)

Substitution   (substitute N from eq1 into eq2]:

     5(2D) + 10D = 2500

      10D + 10D = 2500

          20D = 2500

            D = 125

      N=2D         [eq1 again]

      N=2(125)

      N=250

Check:

  Is   5(250) + 10(125) = 2500   ?

        1250 +  1250 = 2500   ?

          2500 = 2500   ?yes

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The roots of 2x^2-3x=4 are a and b. Find the simplest quadratic equation which has roots 1/a and 1/b
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Find the roots

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we use hmm, completing the suare
2(x²-1.5x)=4
divide both sides by 2
x²-1.5x=2
take 1/2 of linear coeiftn and square it
-1.5/2=-0.75, (-0.75)²=0.5625
add that to both sides
x²-1.5x+0.5625=2+0.5625
factor perfect squaer trinomial
(x-0.75)²=2.5625
square root both sides, remember to take positive and negative square roots
x-0.75=+/-√2.5625
add 0.75 to both sides
x=0.75+/-√2.5625

the roots are x=0.75+√2.5625 and x=0.75-√2.5625

1/a and 1/b
1/(0.75+√2.5625) and 1/(0.75-√2.5625)

if the roots of a quadratic equation are r1 and r2 then it factors to
(x-r1)(x-r2)
so then we can factor our equation to be
(x-\frac{1}{0.75+\sqrt{2.5625}})(x-\frac{1}{0.75-\sqrt{2.5625}})

if we were to try and expand it, we would get
x²+0.75x-0.5
that's the simpliest equation with roots 1/a and 1/b where a and b are he roots of 2x²-3x=4


x²+0.75x-0.5 is answer
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