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3 years ago

1- A car engine's cooling system con-

1 answer:

4 0

The temperature change in water is 9.95°. The temperature change in methanol is 20.65°. Water removes the thermal energy from the engine better.

<h3>What is a cooling system?</h3>

A cooling system is a system that is design to reduce the temperature of a car engine as the car in in operation.

For water;

H = mcθ

H = heat added

m = mass of water

c = heat capacity of water

θ = temperature rise

θ = H/mc

θ = 836.0 × 10^3 J/20 Kg × 4200

θ = 9.95°

For methanol;

mass = density × volume = 0.80 g/cm3 × 20000cm^3 = 16Kg

Hence;

θ = 836.0 × 10^3 J/16Kg × 2530J

θ = 20.65°

The thermal energy that is removed is higher with water.

Learn more about specific heat capacity:brainly.com/question/2530523

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1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:

Mandarinka [93]

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

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3 years ago

Geronimo wants to move an object 12 meters. Calculate the net work done by the object with an applied force of 150 N and a frict

valina [46]

Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

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3 years ago

Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.

GenaCL600 [577]

Answer:

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

$f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$

Here, f is the frequency, L be the length

$f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$ ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

$f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}$ .... (2)

Divide equation (1) by (2)

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

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3 years ago

Which of the following lies in the ecliptic plane?

babymother [125]

<h2>Answer: Earth's orbital path around the Sun</h2><h2></h2>

The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>

<u />

It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about $23\°$ approximately. This is due to the inclination of the Earth's axis.

Hence, the correct option is Earth's orbital path around the Sun.

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4 years ago

a car is rolling backward when it hits the gas. after 8.25 s it is moving forward at 8.62m/s, and is 12.9m to the right of its s

MAXImum [283]

Answer: = . /

Explanation:

The acceleration is

= − 0

In our case, the initial velocity has minus sign.

Thus,

= − (−0) = + 0

Substituting

0 = 2 ( + 0 ) − = 2 + 0 2 −

Thus,

0 2 = 2 −

So,

0 = − = 8.62 − 12.9

8.25 = 7.06 m/s

Answer: = . /

7 0

4 years ago

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