Answer:
-1.82 °C
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 33.9 g
- Mass of water (solvent): 578 g = 0.578 kg
- Freezing point depression constant for water (Kb): -1.82 °C/m
Step 2: Calculate the molality of the solution
We will use the following expression.
m = mass of solute / molar mass of solute × kg of solvent
m = 33.9 g / 58.44 g/mol × 0.578 kg
m = 1.00 m
Step 3: Calculate the freezing point depression (ΔT)
The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:
ΔT = Kb × m
ΔT = -1.82 °C/m × 1.00 m
ΔT = -1.82 °C
Answer:
Microliters = 
Explanation:
SI unit of volume is liter.
..............................(1)
1dm=10cm
.................(2)
replacing value of 
from equation (1) in equation (2)
...................(3)
but
....................(4)
replacing value of 1 liter from equation (3) in equation (4)
on solving further ,we get
Microliters =
<span>K D = 1.0g/ 28 ml 0.0357
-------------- = ---------- = 1.65
1.0 g/46 ml 0.0217
is the distribution coefficient of caffeine in this solvent system</span>
Answer:
Explanation:
NCl3 does not dissolve in water because it is a nonpolar molecule which is different with water. NCl3 is nonpolar due to the difference in electronegativities between 3 atoms of Cl and 1 atom if N2.
