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Art [367]
2 years ago
9

You can identify an element if you know its Atomic number or ___. Fill in the Blank.

Chemistry
2 answers:
Stolb23 [73]2 years ago
7 0

answer: atomic number

ludmilkaskok [199]2 years ago
5 0

Answer:

The answer is Atomic Number

Explanation:

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What is the percent composition by mass of sulfur in the compound MgSO4 (gram formula mass = 120 g/mol)?
slavikrds [6]

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.

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2 years ago
THIS IS SCIENCE
lana [24]
I'm guessing D or C, remember that the noble gases cannot combine
5 0
3 years ago
Why do substances with different structures have similar conductivity values
weeeeeb [17]

Answer:

because of the material, they are made of      

Explanation:

like a paperclip and a car door maybe they both are metal or steel whatever they both can conduct energy. because of what they are made of.

i hope this helps and sorry i am rushing, i also just woke up

7 0
2 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
In a chemical reaction, the reactants (beginning elements or compounds) but have the same number and type of atoms as the produc
AleksAgata [21]

Answer:The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. ... There are two oxygen atoms in the reactants and two atoms of oxygen in the product.

Explanation:

4 0
3 years ago
Read 2 more answers
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