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Hoochie [10]
2 years ago
5

A quadrilateral with no acute angels

Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0

Answer:

Below.

Step-by-step explanation:

One example is a square.

Another is a rectangle.

Both of these contain 4 right angles.

notsponge [240]2 years ago
4 0

Answer:

Squares & Rectangles

Step-by-step explanation:

Both of these quadrilaterals have 90 degree angles (right angles), no acute angles.

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Graph y=1/4x-6 Use the line tool and select two points on the line
DochEvi [55]

Answer:

2 points would be 10 and -10

Step-by-step explanation:


7 0
3 years ago
What is the ratio for the volumes of two similar cylinders, given that the ratio of their heights and radii is 2:3?
ankoles [38]

Answer:

C IS YOUR ANSER.

Step-by-step explanation:

4 0
3 years ago
The algebraic form of an arithmetic sequence is 5n-2<br>a) What is its common difference?​
Alexxandr [17]

Answer:

5

Step-by-step explanation:

[math]

U_{n} = 5n - 2 \\

Common Difference = U_{n+1} - U_{n} \\

= [5(n + 1) - 2] - [5n - 2] = [5n + 5 - 2] - [5n - 2]\\

= 5n + 5 - 2 - 5n + 2\\

= 5

[/math]

5 0
3 years ago
Help pls i really need help
Naddik [55]
<h3>Answer:  33%</h3>

===========================================================

Explanation:

1/3 converts to the decimal form 0.333333... where the 3's go on forever

5/3 is a similar story but 5/3 = 1.666666.... where the '6's go on forever

The notation 0.\overline{6} indicates that the 6's go on forever.

So, 0.\overline{6} = 0.666666\ldots

The horizontal bar tells us which digits repeat. As another example, 0.\overline{123} = 0.123123123123\ldots

The three dots just mean "keep this pattern going forever".

----------

Everything mentioned so far has the decimal portions go on forever repeating some pattern over and over.

The only one that doesn't do this is 33% which converts to the decimal form 0.33

The value 0.33 is considered a terminating decimal since "terminate" means "stop". So this is the value that doesn't fit in with the other three items mentioned.

3 0
2 years ago
A high school debate team of 4 is to be chosen from a class of 35. how many possible ways can the team be formed?
Burka [1]
Imagine there are 4 sits for fill for the debate team 
we can fill the first sit in 35 different ways, second sit we only have 34 choices , third sit 33 and last sit 32 ways to possible fill it. 
35·34·33·32=1,256,640 possible ways the team could be form
4 0
3 years ago
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