A quadrilateral with no acute angels

Mathematics

2 answers:

Fynjy0 [20]1 year ago

8 0

Answer:

Below.

Step-by-step explanation:

One example is a square.

Another is a rectangle.

Both of these contain 4 right angles.

notsponge [240]1 year ago

4 0

Answer:

Squares & Rectangles

Step-by-step explanation:

Both of these quadrilaterals have 90 degree angles (right angles), no acute angles.

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Graph

posledela

Answer:

Step-by-step explanation:

3 0

2 years ago

Did i get this right? if not could you tell me what it is.

barxatty [35]

Let’s simply step-by-step.
-9+1/4x-6-1/8x
=-9+1/4x+-6+-1/8 x
COMBINE LIKE TERMS:
=-9+1/4 x + -6 + -1/8 x
=(1/4 x + -1/8 x) + (-9+-6)
Answer
=1/8x -15

5 0

2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$