Given the graph y = f(x)
The graph y = f(cx), where c is a constant is refered to as horizontal stretch/compression
A horizontal stretching is the stretching of the graph away from the y-axis.
A horizontal compression is the squeezing of the graph towards the
y-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is stretched horizontally by a factor of c units.
If | c | > 1, then the graph is compressed horizontally by a factor of c units.
For values of c that are negative, then the horizontal
compression or horizontal stretching of the graph is followed by a
reflection across the y-axis.
The graph y = cf(x), where c is a constant is referred to as a
vertical stretching/compression.
A vertical streching is the stretching of the graph away from the x-axis. A vertical compression is the squeezing of the graph towards the x-axis. A compression is a stretch by a factor less than 1.
If | c | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of c units.
If | c | > 1, then the graph is stretched vertically by a factor of c units.
For values of c that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
Answer:
Option C. bar graph is the answer.
Answer:
In a command economy, the government controls major aspects of economic production. The government decides the means of production and owns the industries that produce goods and services for the public
Step-by-step explanation:
hope this helps!
Answer:
0.7361
Step-by-step explanation:
In this question we have
number to be 10
Then we have a probability of 10% = 0.10
We have q = 1-p
= 1-0.10 = 0.90
Then the probability of not more than 1 being defective:
P(x=0) + p(x= 1)
(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)
= 1 x1 x0.3487 + 10 x 0.1 x 0.3874
= 0.3487 + 0.3874
= 0.7361
This is the the required probability and this answers the question.
probability = 10 percent = 0.1
q= 1- 10percent = 90% = 0.9
n = 4
To get the required probabiltiy for this question is
P(not greater than one is defective )=P(x=0)+P(x=1)
= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³
= 0.9477
The required probability is 0.9477
