Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
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Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
The last option ,KH and LM
Line Segment AB<span> ≅ Line Segment DB </span>
Answer:
The answer is $80 / $60
Step-by-step explanation:
Answer:
Probability that Jonas gets an orange is 1/4 and Beth gets a peach is 3/16.
Step-by-step explanation:
Here,
The total number of fruits n(S) = 3 + 4 + 4 + 2 + 3
= 16
The total number of oranges n(O) = 4
The total number of peas n(P) = 3
Now,
P(O) = n(O)/n(S)
= 4/16
= 1/4
Again,
P(P)= n(P)/n(S)
= 3/16