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3 years ago

13

The current size of an image on Sandy's computer is shown below:

1 answer:

lukranit [14]3 years ago

7 0

Answer:

D-Length=2 inches Width=3inches

Step-by-step explanation:

Self explanatory, this is the only reasonable answer. The other answers size the image incorrectly to fit the question.

Good luck! Hope this helps!

You might be interested in

A student randomly guesses on 10 true/false questions. use the binomial model to determine the probability that the student gets

lana [24]

Answer:

$P(5)=\frac{63}{256}$

Step-by-step explanation:

we are given

A student randomly guesses on 10 true/false questions

so,

$n=10$

there only true and false

so, probability getting true question is

$p=\frac{1}{2}$

so, probability getting false question is

$q=\frac{1}{2}$

the student gets 5 out of 10 questions right

so,

r=5

we can use binomial probability formula

$P(r)=\frac{n!}{r!(n-r)!} p^rq^{n-r}$

now, we can plug values

$P(5)=\frac{10!}{5!(10-5)!} (\frac{1}{2})^5(\frac{1}{2})^{10-5}$

we can simplify it

and we get

$P(5)=\frac{63}{256}$

4 0

3 years ago

What is the value of the variable that makes the statement true?

Oksanka [162]

$a+(-7)+3=0 \\
a-7+3=0 \\
a-4=0 \\
a=4$

The answer is C. 4.

3 0

3 years ago

Solve for x if log 9 base x + log 3 base x^2 = 2.5

Y_Kistochka [10]

Not sure if the equation is

$\log_9x+\log_3(x^2)=\dfrac52$

or

$\log_x9+\log_{x^2}3=\dfrac52$

If it's the first one:

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}$

$9^{\log_9x+\log_3(x^2)}=x\cdot x^4$

$9^{\log_9x+\log_3(x^2)}=x^5$

On the other side of the equation, we'd get

$9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5$

Then

$x^5=3^5\implies\boxed{x=3}$

If it's the second one instead, you can use the same strategy as above:

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}$

(Note that this step assume $x>0$ )

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}$

$x^{\log_x9+\log_{x^2}3}=9\sqrt3$

Then we get

$9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}$

6 0

3 years ago

What is 1and1/7 out of 100

igor_vitrenko [27]

Answer:

8/7/100 0_0

Step-by-step explanation:

4 0

4 years ago

What is the percent of change from 74 to 112? rounded to the nearest percent

ruslelena [56]

Answer:

The percent of change from 74 to 112 is 51%.

Step-by-step explanation:

Given:

The percent of change from 74 to 112.

Now, the difference between the numbers $112-74=38$ .

Then, calculating the percentage of the result by $74$ .

$\frac{38}{74}\times100$

$=0.5135\times100$

$=51.35%$ .

Round to the nearest percent of $51.35%$ is $51%$ .

Therefore, the percent of change from 74 to 112 is 51%.

4 0

3 years ago