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3 years ago

Please help me factor this quartic polynomial!! and explain how pls! i tried to start it

Mathematics

2 answers:

denpristay [2]3 years ago

6 0

4 (u^2+8)x(u^2+1) try that

Crazy boy [7]3 years ago

5 0

FOIL method
First:
u squared times u squared equals to u to the fourth.
Outer and Inner:
8u squared + u squared equal 9u squared. Remember, the exponents don't change when adding!
Last:
8 times 1 equals 8

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1/4 plus 4/5(3/4x - 1 1/9)

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Answer:

$\frac{3}{5}x+-\frac{131}{180}$

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3 years ago

What is the x in 4x-5=8

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Answer:

x= 3.25

Step-by-step explanation:

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3 years ago

Write equivalent expressions of 18m+42n

serious [3.7K]

Answer:

See explanation

Step-by-step explanation:

Given:

18m + 42n

These two variables are not the same, so we can't add the two terms. However, we can factor out a number out of this expression.

The GCF of 18 and 42 is 6.

We can draw 6 out of this expression to get 6(3m + 7n).

This is an equivalent expression.

We can also draw 2 out to get 2(9m + 21n).

We can also draw 3 out to get 3(6m + 14n).

We can also draw 1/2 out to get (1/2)(36m + 84n).

There are endless possibilities, but these are a few. You get the idea!

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7 0

3 years ago

Read 2 more answers

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liraira [26]

For x such that 0 < x < $\frac{\pi}{2}$ , the mathematical expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

<u>Given the following data:</u>

$\frac{\sqrt{1 \;-cos^2x} }{sinx}$

$\frac{\sqrt{1 \;-sin^2x} }{cosx}$

In Trigonometry, you should take note of the following mathematical expression:

$sin^2x + cos^2x = 1$

Therefore, we can obtain the following:

$sin^2x = 1 - cos^2x$ ...equation 1.

$cos^2x = 1 - sin^2x$ ...equation 2.

Substituting the equations respectively, we have:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = \frac{\sqrt{sin^2x} }{sinx} + \frac{\sqrt{cos^2x} }{cosx}\\\\$

Taking the square roots, we have:

$\frac{sinx}{sinx} + \frac{cosx}{cosx} = 1 +1\\\\1+1=2$

Therefore, for x such that 0 < x < $\frac{\pi}{2}$ , the expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

Read more on trigonometry here: brainly.com/question/4515552

7 0

2 years ago

Read 2 more answers