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2 years ago

Jacob took a total of 12 quizzes over the course of 3 weeks.

Mathematics

1 answer:

harkovskaia [24]2 years ago

7 0

I think its 7.3 not very sure though
Its because if you divide 22(quizzes)by 3(weeks)

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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0

3 years ago

Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 138 to 190 cm and

mart [117]

Answer:

Best predicted value of y' = 86.16 kg

Step-by-step explanation:

Given,

n = 100

Range of heights = 138 - 190cm

Range of weight = 39 to 150 kg

x' =167.46 cm

y' = 81.44 kg

r = 0.108

p value = 0.285

y = - 105 + 1.08x

Significance level = 0.05

We reject H0 since pvalue, 0.285 is less than significance level of 0.05.

Therefore,

Given height of adult male, x = 177 cm

y = - 105 + 1.08x

The best predicted value of y' =

y' = - 105 + 1.08(177)

y' = 86.16 kg

The best predicted value of y' is 86.16kg

6 0

3 years ago

Dawn draws 1 card, replaces it, and draws another card. Is it more likely that she draws 2 red cards or 2 face cards? Can someon

Llana [10]

Red card because it is a fifty fifty chance for the colors but a 3 in 10 chance for a face card

3 0

3 years ago

11. The student council is comparing prices for their semi-formal dance. They compare banquet. Hall A charges $40 per person. Ha

Natalka [10]

Answer:

TC (A) = 40x , TC (B) = 500 + 20x

Step-by-step explanation:

Let the number of students be = x

Hall A Total Cost

Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x

Hall B Total Cost

Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x

4 0

2 years ago

3.) Find the quotient<br> 35)2,520<br> Answer:

AleksAgata [21]

Answer:

1.38888889

Step-by-step explanation:

Do the math on the calculator to get the answer.

3 0

3 years ago