16y=6x+42
16/16y=6x/16+42/16
y= 3x/8 + 21/8
First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
2(5m+4)=2(3m-10)
10m+8= 6m-20
-6m -6m
4m+8= -20
-8 -8
4m= -28
m = -7
Answer:

Step-by-step explanation:
Equation: 
Jalil says it is not possible to isolate x because x has a different unknown coefficient.
Victoria t. Victoria believes there is a solution
Solving the equation:




So, this shows x can be isolated .
Victoria was right .
It was not possible to isolate x if the coefficients of x would be same .
But in the given equation the coefficients of x are not same .
So, Victoria is right.