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Vesna [10]
2 years ago
10

LOOK AT THE PICTURE BELOW

Mathematics
2 answers:
Katyanochek1 [597]2 years ago
8 0

Answer:

The area of the rectangle is 40 and the area is the triangle is 20 therefore, the area of the shape is 60

Step-by-step explanation:

Rectangle:

8cm x 5cm = 40cm

Triangle <em>(</em><em>1</em><em>/</em><em>2bxh</em><em>)</em>

The base of the triangle would be 8 cm as the top and the bottom of the rectangle is the same width. The height was given to be 5 cm (<em>note the height is the dotted line</em>) Therefore the area of the triangle is half the base which is (8×1/2 = 4) times the height (5); which is 20.

slava [35]2 years ago
4 0

Answer:

60 cm2

32.48 sq.ft

Step-by-step explanation:

The area of the first image is:

A=A_{t} +A_{r} =\frac{bh}{2} +bh =\frac{(8)(5)}{2} +(8)(5)=20+40=60cm^{2}

The área of the second image:

Hope this helps

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An equilateral triangle has perimeter P. The length of one side is P/3. Which expression is equivalent to the length on one side
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Answer: 3\times \dfrac{P}{3}=P

Step-by-step explanation:

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7.2

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a good method towards percentages in multiplying both numbers in this case 48 and 15 and then lowering the product by 2 decimal places

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The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
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