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3 years ago

Write en equation if y=75 when x=500.Find your answer in the answer column and notice the two letters next to it.

Mathematics

1 answer:

Mila [183]3 years ago

4 0

The answer would be about y = 6.67x

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Josephine wants to put a wallpaper border around the ceiling of her room. The dimensions are 7 ft and 3 inches and 8 feet and 3

Ilya [14]

Answer:
372inches or 31feet
How to:
7feet and three inches is equal to 87 inches and 8ft and 3 inches is equal to 99 inches. Then you know that both sides have to be multiplied by two because there are four sides in the room. Meaning you have 174in and 198in. Then you add those together to get your answer which is 372. To get back to feet just divide by twelve.

8 0

3 years ago

What is the value of x? 52° 93° (x + 3) 78°

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

Step One

Find the exterior angle connected to the 93 degree angle. It is also a supplement to 93. Supplementary angles add to 180. Call the exterior angle y

93 + y = 180 Subtract 93 from both sides

y = 180 - 93

y = 87

Step two

Add all the exterior angles. They equal 360

x + 52 + 87 + x + 3 + 78 = 360 Combine the like terms

Step 3

Solve the equation

2x + 220 = 360 Subtract 220 from both sides

2x = 360 - 220

2x = 140 Divide by 2

x = 70

I don't see that anywhere, but I'm pretty sure I'm right.

4 0

3 years ago

Can you find 10/21 of 3/ 10

hoa [83]

0.1428571428 would be the correct answer

5 0

3 years ago

Simplify -10(10w-6-w)-w

kompoz [17]

Answer:

-91w + 60

Step-by-step explanation:

to simplify this -10(10w-6-w)-w

we have,

-10(10w-6-w)-w

-100w + 60 + 10w - w

-91w + 60

6 0

3 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago