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2 years ago

Cindy's age, x, is 3 times her age 6 years ago.

Mathematics

1 answer:

Ugo [173]2 years ago

3 0

The algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).

The given statement is Cindy's age, x, is 3 times her age 6 years ago.

We need to represent the given statement as the algebraic expression.

<h3>What is an algebraic expression?</h3>

In mathematics, an algebraic expression is an expression built up from integer constants, variables, and algebraic operations.

6 years ago Cindy's age(x) is x-6.

3 times Cindy's age=3(x-6)

Therefore, the algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).

To learn more about the algebraic expression visit:

brainly.com/question/953809.

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The ratio of bOYS to giris

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Answer:

There were a total of 40 girls there

Step-by-step explanation:

32 divided by 4 is 8

So multiply 8 x 5 to get 40

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3 years ago

PLS HELP QUICKLY !!!!!!

Olegator [25]

Answer: Choice C)

--------------------------------------

mean = xbar = (2400+1750+1900+2500+2250+2100)/6
mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250
1750-2150 = -400
1900-2150 = -250
2500-2150 = 350
2250-2150 = 100
2100-2150 = -50
The differences are: 250, -400, -250, 350, 100, -50

Then you square those values and add up the squares

(250)^2 + (-400)^2 + (-250)^2 + (350)^2 + (100)^2 + (-50)^2 = 420,000

3 0

3 years ago

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The sum of the first term of an ap is 240 and the sum of the next 4 term is 220 find the first term of the ap

Sindrei [870]

Answer:

The common difference is -5/4

T(n) = T(0) - 5n/4,

where T(0) can be any number. d = -5/4

Assuming T(0) = 0, then first term

T(1) = 0 -5/4 = -5/4

Step-by-step explanation:

T(n) = T(0) + n*d

Let

S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240

S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220

S2 - S1

= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)

= (5+6+7+8 - 1 -2-3-4)d

= 4(4)d

= 16d

Since S2=220, S1 = 240

220-240 = 16d

d = -20/16 = -5/4

Since T(0) has not been defined, it could be any number.

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3 years ago

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per hour. At

kumpel [21]

Answer:

The required piece-wise linear function is

$\left\{\begin{matrix}1.5x & 0\leq x$

Step-by-step explanation:

Consider the provided information.

Let x represents the number of hours and S(x) represents the depth of snow.

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per.

That means the depth of snow will be:

$S(x)=1.5x\ \ \ 0\leq x< 4$

At 4:00 a.m., it starting falling at a constant rate of 3 inches per hour,

From mid night to 4:00 a.m the depth of snow will be 1.5×4=6 inches.

If we want to calculate the total depth of snow from midnight to 7:00 am we need to add 6 inches in 3(x-4) where 4≤x<7

Therefore,

$S(x)=3(x-4)+6\ \ \ 4\leq x$

7:00 a.m. to 9:00 a.m., snow was falling at a constant rate of 2 inches per hour.

From mid night to 7:00 a.m the depth of snow will be 3(7-4)+6=15 inches.

If we want to calculate the total depth of snow from midnight to 9:00 am we need to add 15 inches in 2(x-7) where 7≤x≤9

$S(x)=2(x-7)+15\ \ \ 7\leq x\leq 9$

Therefore, the required piece-wise linear function is

$\left\{\begin{matrix}1.5x & 0\leq x$

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3 years ago

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