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1 year ago

Cindy's age, x, is 3 times her age 6 years ago.

Mathematics

1 answer:

Ugo [173]1 year ago

3 0

The algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).

The given statement is Cindy's age, x, is 3 times her age 6 years ago.

We need to represent the given statement as the algebraic expression.

<h3>What is an algebraic expression?</h3>

In mathematics, an algebraic expression is an expression built up from integer constants, variables, and algebraic operations.

6 years ago Cindy's age(x) is x-6.

3 times Cindy's age=3(x-6)

Therefore, the algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).

To learn more about the algebraic expression visit:

brainly.com/question/953809.

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- A number r added to 3.7 is less than 1.2.

SIZIF [17.4K]

Answer:

3.7 + r < 1.2

Step-by-step explanation:

a number r added to 3.7 is 3.7 + r

New expression 3.7 + r should be less than 1.2 --->

3.7 + r < 1.2

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3 years ago

A rectangular field is 300 meters long and 250 meters wide. What is the area of the field in square kilometers

lidiya [134]

Answer:

0.075 sq km

Step-by-step explanation:

Given that there is a rectangular field with dimensions of length =300 m and width = 250 m.

We have to calculate area of this rectangle in the units of square kilometres.

Let us convert length and width into km

1000m = 1 km

Hence length = 300/1000= 0.3 km and

width = 250/1000 = 0.25 km.

ARea = length x width = 0.3 x 0.25

=0.075 square km.

7 0

2 years ago

A rock is tossed upward. Its height after t seconds is given by S = −16t2 + 24t + 3 feet. What is its maximum height? When does

Mama L [17]

Answer:

Step-by-step explanation:

The height of the rock ,(s), in feets after t seconds is given by the function

S = −16t^2 + 24t + 3

The given function is a quadratic equation. If values of height attained is plotted against time, the shape of the graph will be a parabola whose vertex would correspond to the maximum height obtained by the object.

Vertex of the parabola = -b/2a

a = - 16

b = 24

Vertex = - 24/- 16×2 = 24/32

Vertex = 0.75

So the maximum height is 0.75 feet

To determine the time at which it will reach a maximum height of 0.75, we will substitute s = 0.75 into the equation.

S = −16t^2 + 24t + 3

0.75 = −16t^2 + 24t + 3

−16t^2 + 24t + 2.25 = 0

Applying the general formula for quadratic equation,

t = b ± √b^2 - (4ac)]/2a

a = -16

b = 24

c = 2.25

t = - 24 ± √24^2 - 4(-16 × 2.25)]/2×-16

t = - 24 ± √(576 + 144)]/-32

t = - 24 ± √(720)/-32

t = (- 24 ± 26.83)/-32

t = 2.83/-32 or t = -50.83 /-32

t = - 0.088 or t = 1.588

The time cannot be negative so,

The time take to reach maximum height is 1.588 seconds

4 0

3 years ago

the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2

lilavasa [31]

Answer: c) $\dfrac{3}{2}$ .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

$\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}$