1 year ago

(sin (x+y)) / sinxcosy = 1+ cot(x) + tan(y)

Mathematics

1 answer:

ivann1987 [24]1 year ago

5 0

Answer:

sin (×+y)/sinx cosy =1+ cotx tany

from trig ratio Sin [x +y] = sinx Cosy + cosx siny

Sinx cosy + cosox siny./Sinx cosy

then check the attachments for further information

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What are the zeros of the following quadratic equation: y = 6x2 - 17x - 3

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Hi there!

$y = 6x^2 - 17x - 3$

Factor by grouping:

$y = 6x^2 - 18x+1x - 3\\y = 6x(x- 3)+1x - 3\\y = 6x(x- 3)+(x - 3)\\y = (6x+1)(x- 3)$

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