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olga nikolaevna [1]
2 years ago
14

Can someone help me here

Mathematics
2 answers:
Vinil7 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

Remark

When a quadrilateral is inscribed in a circle, the opposite angles are supplementary. x is opposite 112 degrees. Therefore x and 112 add up to 180 degrees.

Formula

x + 112 = 180                      Subtract 112 from both sides.

Solution

x + 112-112 = 180 - 112

x = 68

Answer

x = 68

Tems11 [23]2 years ago
5 0

Answer:

Step-by-step explanation:

#9.

x° = 200° and x = 200

y° = 100° and y = 100

#10.

x° = 68° , x = 68

y° = 99° , y = 99

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maks197457 [2]

Answer:

13 1/8

Step-by-step explanation:

3/2* 7/2*5/2

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3 years ago
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

p = \frac{4}{6} = 0.6667

10 normal six sided dice are thrown.

This means that n = 10

Find the probability of obtaining at least 8 failures.

This is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951

P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867

P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174

Then

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992

0.2992 = 29.92% probability of obtaining at least 8 failures.

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Step-by-step explanation:

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