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2 years ago

Is it possible to draw a triangle with angles 150°, 20° and 20°? Explain your answer.

Mathematics

1 answer:

Maksim231197 [3]2 years ago

7 0

Answer:

No, it is not possible.

Step-by-step explanation:

The Triangle Sum Theorem states that all the interior angles of a triangle will always add up to 180°, but 150 + 20 + 20 = 190.

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VashaNatasha [74]

Answer:

Step-by-step explanation:

To one decimal place:

$2 \sqrt{10} = 6.3$

$10 \sqrt{2} = 14.1$

So there are eight integers between 2√10 and 10√2: 7, 8, 9, 10, 11, 12, 13, and 14.

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1 year ago

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In the figure, identify the types of angles in the table below .

Anna007 [38]

Answer:

∠1 and∠3 = Supplementary Angles

∠4and∠5 = Complementary Angles

∠5and∠1 = Adjacent Angles

∠2and∠3 = Supplementary Angles

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3 years ago

8 less than twice a number is twelve .

kvv77 [185]

8 - -2×2=12.............

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2 years ago

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<img src="https://tex.z-dn.net/?f=9x%20%7B%7D%5E%7B2%7D%20y%20%7B%7D%5E%7B3%7D%20z%20%7B%7D%5E%7B5%7D%20%20%5Cdiv%206x%20%7B%7D%

dexar [7]

Answer:

3y²z³ / 2x

Step-by-step explanation:

we can take one term at a time:

9/6 can be simplified to 3/2

x²÷x³ = x^-1 which equals $\frac{1}{x}$

y³÷y = y²

z⁵÷z² = z³

put it all together:

3· $\frac{1}{x}$ ·y²·z³ / 2 or

3y²z³ / 2x

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3 years ago

In ΔABC, if AB = 14 and BC = 9, AC may be equal to

Pie

Answer:

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Step-by-step explanation:

There is a fact in any triangle:

<em>The length of any side of a triangle must be greater than the difference of the lengths of the other two sides and smaller than the sum of the lengths of the other two sides</em>

If the lengths of the three sides of a triangle are a , b and c, then

a - b < c < a + b
b - c < a < b + c
a - c < b < a + c

In Δ ABC:

→ (BC) - (AC) < AB < (BC) + (AC)

→ (AB) - (AC) < BC < (AB) + (AC)

→ (AB) - (BC) < AC < (AB) + (BC)

∵ AB = 14 units

∵ BC = 9 units

- Find the sum and difference of them

∵ AB - BC = 14 - 9

∴ AB - BC = 5

∵ AB + BC = 14 + 9

∴ AB + BC = 23

- That means the length of AC could be any integer greater

than 5 and smaller than 23

∴ 5 < AC < 23

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

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3 years ago

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