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Over [174]
2 years ago
5

Corbin made a scale model of the San Jacinto Monument. The monument has an actual height of 604 feet. Corbin's model used a scal

e in which 1 inch represents 100 feet. What is the height in inches of Corbin's model?
Mathematics
1 answer:
photoshop1234 [79]2 years ago
8 0

<u>Answer: </u><u>6.04 inches</u>

<u>Step-by-step explanation:</u>

The actual height of the monument = 604 feet

The scale used by Corbins is 1 inch = 100 feet

The height of the Corbins model in inches= \frac{604}{100} = 6.04 inches

the height of the Corbins model = 6.04 inches

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MatroZZZ [7]

Answer: No one ever answers

Step-by-step explanation:

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3 years ago
Which of the following represents the correct calculation of the sampling interval?
Goshia [24]

Answer:

The correct answer is

d. Sampling Interval = Population size ÷ Sample size.

Step-by-step explanation:

According to Johnstone et al., (2014) "<em>Once the auditor has determined the appropriate sample size, a sampling interval is calculated by dividing the population size by the sample size.</em>"

Thus,

Sampling Interval = Population size ÷ Sample size.

Johnstone, K., Rittenberg, L. and Gramling, A. (2014). <em>Auditing: A Risk-Based Approach to Conducting a Quality Audit.</em> Ninth Edition.

4 0
4 years ago
On Saturday, mason biked 1.5 hours at a speed of 11.9 miles per hour. on Sunday, he biked 3.2 hours at a speed of 14.8 miles per
solniwko [45]
1.7 miles: subtract 1.5 from 3.2 which equals 1.7 (make sure to line up the decimals!)

3 0
4 years ago
The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​
Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

                            a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0
3 years ago
At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi
alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

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- The new method is distributed X ~ Poisson(L = 5)

P(X=x)=\frac{L^{x}e^{-L}}{x!}

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events  (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367

- For the new method:

P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

7 0
3 years ago
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