Answer:

Step-by-step explanation:
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<u>Distance formula</u>

Let P(x, y) = any point on the locus
Let A = (0, 2)
Let B = (-2, 3)
If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

Therefore, using the distance formula:

Square both sides:
![\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2%2B%28y-2%29%5E2%3D%5Cdfrac%7B1%7D%7B9%7D%5B%28x%2B2%29%5E2%2B%28y-3%29%5E2%5D)

Multiply both sides by 9:



It would be the same distance...She could drive 12 miles west then 10 north or take the same route she came back...Brainliest?....
Answer:
P(B) 7
Step-by-step explanation:
The answer is P (B)
Hello! 3x + 20 and 8x - 5 are equal. To find the value of "x", we should set up and solve an equation. It would be written like this:
3x + 20 = 8x - 5
First off, subtract 3x from both sides in order to get 20 = 5x - 5. Add 5 to both sides to get 25 = 5x. Now, divide each side by 5 to isolate the "x". 25/5 is 5. Now, let's plug in the value and see if it works. 3 * 5 is 15. 15 + 20 is 35. 8 * 5 is 40. 40 - 5 is 35. 35 = 35. There. x = 5.