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Tema [17]
3 years ago
5

Given x and y are integers, explain why the product of the expression and it's conjunct will always be an integer

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

If neither of the two real numbers is zero, then their product is also not zero Suppose also that x is a real number that satisfies the equation The " / " symbol does not always give you a result of an integer, so be careful.pkek, and any other expression for n as a product of prime numbers is identical to this except,.

Step-by-step explanation:

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Answer:

1/6, 1/6, 630

Step-by-step explanation:

1/6*n-7≤98

1/6*n≤98+7

1/6*n≤105

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n≤630

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Answer:

a= -1

b=-9

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Step-by-step explanation:

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Simora [160]

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3 0
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Read 2 more answers
Find the solutions to x2 = 28.
mr Goodwill [35]

Answer: x = \pm2\sqrt{7}\\\\

Work Shown:

x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}\\\\

This can be rewritten into x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}

7 0
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