<span>3-2(Cosx)^2 - 3Sinx = 0.
Recall (Sinx)^2 + (Cosx)^2 = 1.
Therefore (Cosx)^2 = 1 - (Sinx)^2
Substitute this into the question above.
</span><span>3-2(Cosx)^2 - 3Sinx = 0
3 - 2(1 - (Sinx)^2) - 3Sinx = 0 Expand
3 - 2 + 2(Sinx)^2 - </span><span><span>3Sinx = 0</span>
1 + 2(</span><span>Sinx)^2 - 3Sinx = 0 Rearrange
2(Sinx)^2 </span><span><span>- 3Sinx + </span>1 = 0
Let p = Sinx
2p^2 - 3p + 1 = 0 Factorise the quadratic expression
2p^2 - p - 2p +1 = 0
p(2p -1) - 1(2p -1) = 0
(2p-1)(p -1) = 0
Therefore 2p-1=0 or (p-1) = 0
2p=0+1 or (p-1) = 0
2p=1 or p = 0 +1.
p=1/2 or p = 1 Recall p = Sinx
Therefore Sinx = 1/2 or 1.
For 0<u><</u>x<u><</u>360
Sinx =1/2, x = Sin inverse (1/2) , x = 30,
(180-30)- 2nd Quadrant = 150 deg
Sinx = 1, x = Sin inverse (1) , x = 90
Therefore x = 30,90 & 150 degrees.
Cheers.</span>
The equation is: 
and Julianne will begin making a profit after 168 days.
<em><u>Explanation</u></em>
Her total start-up cost is $52,000.
Each day, she spends $650 on operating costs (like utilities and wages) and she earns $960 per day from her students' lesson fees.
If the number of days to overcome the start-up cost is 
, then
the total operation cost spent in days 
and
the total students' lesson fees earned in days 
<em><u>Part A:</u></em> The equation to represent the situation will be:
<u><em>Part B:</em></u><em> </em><em> </em>Julianne will begin making a profit when....
So, Julianne will begin making a profit after 168 days.
Remember you can do anything to an equation as long as you do it to both sides
(y/4)-49=-9
isolate the variable
add 49 to both sides
y/4=40
multiply both sides by 4 to clear fraction
y=160
Answer:
D. 10
Step-by-step explanation:
To find the slope of the equation, we first need to put the equation into slope-intercept form:
y=mx+b
So first, we need to get y by itself.
10x-y=2
Subtract 10x from both sides.
-y=-10x+2
Then, divide -1 on both sides.
y=10x-2
Slope=10
Answer:
3x^2 -7x +2
Step-by-step explanation:
(15x^2 -35x +10)÷5
15/5 x^2 -35/5 x +10/5
3x^2 -7x +2
