Answer:
The ice chunk will take 2.47 seconds to hit the water.
Explanation:
Height from which ice chunk fell = h = 30.0 m
Initial velocity of the ice chunk = u = 0 m/s
Time taken by ice chunk to cover 30.0 m of height = t
Acceleration due to gravity = g 
Using second equation of motion ;



The ice chunk will take 2.47 seconds to hit the water.
If your choices are the following:
A. 1-inch IMC.
B. 1-inch rigid conduit.
C. 3/4 inch IMC.
D. 1/2 inch EMT.
Then the answer is C.
Answer:
83.20 g of Na3PO4
Explanation:
1 mole of Na3PO4 contains 3 moles of Na+.
Mole of Na ion to be prepared = Molarity x volume
= 0.700 x 725/1000
= 0.5075 mole
If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:
0.5075/3 x 1 = 0.1692 mole of Na3PO4
mole of Na3PO4 = mass/molar mass = 0.1692
Hence, mass of Na3PO4 = 0.1692 x molar mass
= 0.1692 x 163.94
= 83.20 g.
83.20 g of Na3PO4 will be needed.
Answer:
Explanation:
From the given information:
TO start with the molarity of the solution:

= 0.601 mol/kg
= 0.601 m
At the freezing point, the depression of the solution is 

Using the depression in freezing point, the molar depression constant of the solvent 


The freezing point of the solution 

The molality of the solution is:

Molar depression constant of solvent X, 
Hence, using the elevation in boiling point;
the Vant'Hoff factor 


Mass of H₂ needed to react with O₂ : 1.092 g
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
Reaction
O₂(g) + 2H₂(g) → 2H₂O(g)
mass of O₂ : 8.75 g
mol O₂(MW=32 g/mol) :

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

Mass H₂ (MW=2 g/mol) :
