This would decrease by 25 hope this helps !!
Answer:
See explanation
Explanation:
Hello there!
In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:
Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:
![Ksp=[Ag^+][Cl^-]](https://tex.z-dn.net/?f=Ksp%3D%5BAg%5E%2B%5D%5BCl%5E-%5D)
And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:
I - 0 0
C - +x +x
E - x x
Which leads to the following modified equilibrium expression:
Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.
Regards!
The balanced chemical reaction:
K2SO4 + O2 = 2KO2 + SO2
Assuming that the reaction is complete, all of the potassium sulfate is consumed. We relate the substances using the chemical reaction. We calculate as follows:
7.20 g K2SO4 ( 1 mol / 174.26 g) ( 1 mol O2 / 1 mol K2SO4 ) ( 32 g / 1 mol ) = 1.32 g O2 consumed in the reaction.
Answer: 1820 mL (to 3 sf)
Explanation:
The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.
From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.
So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.
Substituting into the molarity formula,
- 0.250 = 0.45586725901491/(liters of HCl)
- liters of HCl = 0.45586725901491/0.250
- liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
