Answer:
m = 4.58 g.
Explanation:
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In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:
As we can calculate the moles of propane given the pressure, temperature and volume as shown below:
Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:
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I have a question, my other account got banned too, how long does brainly ban someone?
Answer : The molar mass of catalase is, 
Explanation :
Formula used :
where,
= osmotic pressure = 0.745 torr = 0.000980 atm (1 atm = 760 torr)
C = concentration
R = solution constant = 0.0821 L.atm/mol.K
T = temperature = 
w = mass of catalase = 10.03 g
M = molar mass of catalase = ?
V = volume of solution = 1.05 L
Now put all the given values in the above formula, we get:
Therefore, the molar mass of catalase is,
Answer: 0.4533mol/L
Explanation:
Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol
68g of CaCO3 dissolves in 1.5L of solution.
Xg of CaCO3 will dissolve in 1L i.e
Xg of CaCO3 = 68/1.5 = 45.33g/L
Molarity = Mass conc.(g/L) / molar Mass
Molarity = 45.33/100 = 0.4533mol/L
Answer:
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.
Explanation:
